minta penjelasananya dong ama penyelesaian nya
Jawaban:
b. { 2, 4 }
Penjelasan dengan langkah-langkah:
[tex] log_{2}( {x}^{2} - 4x +1 0) = log_{2}(2x + 2) \\ {x}^{2} - 4x + 10 = 2x + 2 \\ {x}^{2} - 4x - 2x = 2 - 10 \\ {x}^{2} - 6x = - 8 \\ {x}^{2} - 6x + ( - 3) {}^{2} = - 8 + ( - 3) {}^{2} \\ {x}^{2} - 6x + ( - 3) {}^{2} = 1 \\ (x - 3) {}^{2} = 1 \\ \sqrt{(x - 3) {}^{2} } = \sqrt{1} [/tex]
[tex]x _{1} \\ x - 3 = 1 \\ x = 1 + 3 \\ x = 4[/tex]
[tex]x _{2} \\ x - 3 = - 1 \\ x = 2[/tex]
[answer.2.content]
